SQL: Show all tables sorted by size in descending order

This can be done easily via SQL command:

SELECT
    table_name AS `Table`,
    round(((data_length + index_length) / 1024 / 1024), 2) AS `Size (MB)`
FROM
    information_schema.TABLES
WHERE
    table_schema = DATABASE()
ORDER BY
    (data_length + index_length) DESC;

Example output:

+---------------------------------------------------------+-----------+
| Table                                                   | Size (MB) |
+---------------------------------------------------------+-----------+
| cache_hash                                              |  1742.58  |
| sys_history                                             |   680.08  |
| cache_pages                                             |   172.09  |
| sys_log                                                 |   150.23  |
| sys_file_processedfile                                  |    81.80  |
| tt_content                                              |    59.35  |
| sys_refindex                                            |    55.28  |
| tx_extensionmanager_domain_model_extension              |    44.14  |
| sys_file_reference                                      |    43.16  |
| sys_file                                                |    34.64  |
...

By the way, we have described how to exclude unnecessary tables from a dump in another snippet.